Constructor Detail

• DSFileSpec

  public DSFileSpec(java.lang.String dsName,
            java.lang.String dsFileName)

  Specify a file with the given DataSource name and filename, without specifying a fileType or fileFormat.

  Parameters:

  dsName - The name of the DataSource

  dsFileName - The name of the file, without any extension for type or format

• DSFileSpec

  public DSFileSpec(java.lang.String dsName,
            java.lang.String dsFileName,
            java.lang.String dsFileType)

  Specify a file with the given DataSource name, filename, and fileType, without specifying a fileFormat.

  Parameters:

  dsName - The name of the DataSource

  dsFileName - The name of the file, without any extension for type or format

  dsFileType - The fileType (e.g. "ds" for datasource)

• DSFileSpec

  public DSFileSpec(java.lang.String dsName,
            java.lang.String dsFileName,
            java.lang.String dsFileType,
            java.lang.String dsFileFormat)

  Specify a file with the given DataSource name, filename, fileType, and fileFormat.

  Parameters:

  dsName - The name of the DataSource

  dsFileName - The name of the file, without any extension for type or format

  dsFileType - The fileType (e.g. "ds" for datasource)

  dsFileFormat - The fileFormat (e.g. "xml" or "js")

• DSFileSpec

  public DSFileSpec(java.util.Map record)

  Specify a file from a Map specifying one or more of fileName, fileType and fileFormat.

  Parameters:

  record - A Map specifying one or more of fileName, fileType and fileFormat.

• DSFileSpec

  public DSFileSpec(java.lang.String url)

  Construct a DSFileSpec from a URL-like string.

  Parameters:

  url - URL-like specification for the file.

  To specify both the dsName and the filename, use a URL that looks like ds://datasourceName/fileName.type.format -- e.g. "ds://projects/bigProject.proj.xml"). Note that the fileType and fileFormat should not have any spaces.

  If you want a DSFileSpec that only parses the filename, then just specify the filename, like this "fileName.type.format".

Method Detail

• getDataSourceName

  public java.lang.String getDataSourceName()

  Returns:

  The name of the DataSource in which to find the file

• setDataSourceName

  public void setDataSourceName(java.lang.String name)

  Parameters:

  name - The name of the DataSource in which to find the file

• getFileName

  public java.lang.String getFileName()

  Returns:

  The fileName, without any extension for type or format.

• setFileName

  public void setFileName(java.lang.String name)

  Parameters:

  name - The fileName, without any extension for type or format.

• getFileType

  public java.lang.String getFileType()

  Returns:

  The fileType, e.g. "ds"

• setFileType

  public void setFileType(java.lang.String type)

  Parameters:

  type - The fileType, e.g. "ds"

• getFileFormat

  public java.lang.String getFileFormat()

  Returns:

  The fileFormat, e.g. "xml" or "js"

• setFileFormat

  public void setFileFormat(java.lang.String format)

  Parameters:

  format - The fileFormat, e.g. "xml" or "js"